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How many natural gas therms are required to heat a 60 gal water tank from 55F to 140F?
Wiki User
∙ 16y ago
1 therm = 1.05 X 108 joules
1 gallon = 3.79 liters
60 gallons X 3.79 = 227.4 liters
Water = 1g/mL = 1000g/1000mL = 1kg/1L
227.4L = 227.4 kg
Specific heat of water = 4,186 j/kg°C
140°F = 60°C
55°F = 12.78°C
Q = mC∆T
Q1 = (227.4 kg)(4,186 j/kg°C)(60°C - 12.78°C)
Q1 = 4.495 X 107
(4.495 X 107 j)(1 therm/1.05 X 108 j) = 0.428 == ==
Wiki User
∙ 16y ago
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