To get the three number that is divisible by 4 you will take the difference 4^3 and 4^2.
A number is divisible by 4 if the last two digits form a number that is divisible by 4, for example 612 is divisible by 4 (because 12 is divisible by 4).
Get the last two digits of the number. If that number is divisible by 4 then that number is divisible by 4. Example : 2393844 The last two digits are 44 and since 44/4 = 11 or 44 is divisible by 4 then the number 2,393,844 is divisible by 4.
There are infinitely many numbers divisible by 5 and 4. 680 is one of them.
A number is divisible by 4 if the last two digits form a number that is divisible by 4, e.g. 312 is divisible by 4 (because 12 is divisible by 4).
If the last two digits of a number are divisible by 4, the whole number is divisible by 4.
If a number is divisible by 4, the last two digits are divisible by 4. For example, the number 314 is not divisible by 4, but 316 is divisible by 4, because 16 is divisible by 4.
If the last number is divisible by 4 then the whole number is divisable by 4
There is no number that is "divisible by 4" and "not divisible by 4" at the same time - a number cannot be both a multiple of 4 and not a multiple of 4.
There can't be any such number.' 4 ' itself is divisible by 2, so any number divisible by 4 must also be divisible by 2.
if the number formed by the last two digits is divisible by 4, then the whole number will be divisible by 4 for example, 932 is divisible by 4 because 32 is divisible by 4 19935 is not divisible by 4 because 35 is not divisible by 4 (note: if the last two digits are 00, the number is divisible by 4)
Any number (however many digits) that is divisible by 3 and by 4 MUST be divisible by 6. So there cannot be a number that meets the requirements of the question.