20 number
10001
10000
100. Palindromic numbers for the range 10000 to 20000 are 5 digits numbers of the form abcba. The first digit ('a') must be '1'. There are 10 possible digits for 'b' (0-9) and for each of these 10 possible digits for 'c' Thus there are 1 x 10 x 10 = 100 palindromic numbers between 10000 and 20000.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
It is 180,001.
89999 Any whole number above 99999 has 6 or more digits, and any whole number below 10000 has 4 or less digits. Since there are only whole numbers involved, it is a simple subtraction of 10000 from 99999.
The answer to this is .... all the numbers between 999 and 10000
10001
10000.......1(including 198 zero between 1s)
10000
100. Palindromic numbers for the range 10000 to 20000 are 5 digits numbers of the form abcba. The first digit ('a') must be '1'. There are 10 possible digits for 'b' (0-9) and for each of these 10 possible digits for 'c' Thus there are 1 x 10 x 10 = 100 palindromic numbers between 10000 and 20000.
There is an infinity of numbers between 8500 and 10000. For example 8605+sqrt(2).
There are 5 digits in the number 10000.
It is 10000.If you meant ONLY 2 digits alike, then it is 10023.
solution: we know that there are 25 prime numbers are between 1-100 and 168 prime numbers less than 1000. 100 x 100=10000(5 digits) 999 x 999=998001(6 digits) 1000 x 1000=1000000(7 digits) so our answer should be same as the number of prime numbers between 100 to 999. hence, 168-25=143. 143 prime numbers will be there less than 1000 whose square has 5 or 6 digits.
12500 is the average of the two numbers
It's the number that has more digits to the left of the decimal point (if there is no decimal point, it's the number with more digits). If the number of digits to the left of the decimal point is the same, find the position farthest to the left where the digits are different. The number with the greater of those two digits is the greater number. For example, 10000 is greater than 9999 because 10000 has more digits, and 6350 is greater than 6349 because the farthest-left position that is different is the tens place, and 5 is greater than 4.