6 (4/8/12/16/20/24)
There are 25 numbers between 101 and 201 that are divisible by four.
Since 100/4 = 25, there are 25 numbers between 0 and 100 divisible by 4.
25 if you include 100.
To find the numbers between 1 and 100 inclusive that are divisible by either 9 or 4, we first determine how many numbers are divisible by 9 and how many are divisible by 4. There are 11 numbers divisible by 9 (9, 18, 27, ..., 99) and 25 numbers divisible by 4 (4, 8, 12, ..., 100). However, we must be careful not to double-count numbers divisible by both 9 and 4 (36, 72). Therefore, the total number of numbers divisible by 9 or 4 between 1 and 100 inclusive is 11 + 25 - 2 = 34.
There are 3598 numbers between 10000 and 99999 which are divisible by 25. They are elements of the set of numbers of the form 25*k, where k is an integer between 41 and 3999 (inclusive).
for 2 its 50 for 4 its 25
24. 25 if you include 50.
To find how many numbers between 1 and 300 are divisible by 3 or 4, we can use the principle of inclusion-exclusion. The count of numbers divisible by 3 is ( \lfloor 300/3 \rfloor = 100 ), and those divisible by 4 is ( \lfloor 300/4 \rfloor = 75 ). The numbers divisible by both (i.e., by 12) are ( \lfloor 300/12 \rfloor = 25 ). Thus, the total count is ( 100 + 75 - 25 = 150 ). Therefore, there are 150 numbers between 1 and 300 that are divisible by either 3 or 4.
625 is divisible by these five numbers: 1, 5, 25, 125, 625.
100 ÷ 4 = 25 → 24 numbers between 0 and 100 exclusive are divisible by 4 100 ÷ 6 = 16 2/3 → 16 numbers between 0 and 100 are divisible by 6 lcm(4, 6) = 12 → 100 ÷ 12 = 8 1/3 → 8 numbers between 0 and 100 are divisible by 4 and 6.
25
There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.