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There are only five distinct odd digits.
two
5555
You had me until "product." The product of 4 digits can't be prime.
Using the digits, we can make 81 x 62 equals 5022, which is the largest possible product. To make the smallest possible product, do 268 x 1 = 268.
If you mean, "What is the largest number of digits possible in the product of two 2-digit numbers" then 99 * 99 = 9801, or 4 digits. Anything down to 59 * 17 = 1003 will have 4 digits.
It can have 4 digits, because the highest possible two digit numbers 99*99=9801.
There are only five distinct odd digits.
Forming three three digit numbers that use the numbers 1-9 without repeating, the highest product possible is 611,721,516. This is formed from the numbers 941, 852, and 763.
two
5555
4,536 whole numbers or mixed numbers. 5,040 pure decimals.
1,2,3,4 1+2+3+4=10 4 times 3 times 2 times 1 =24 24 counting numbers
x is 987 subtract y is 123 ,which 987-123=864.
It should be obvious (it is, isn't it? am I expecting too much of today's educational system?) that the largest possible result of multiplying two two digit numbers is 99x99 = 9801, which has four digits, and the smallest possible result is 10x10 = 100, which has three digits.
67/72 of them.
52 is a number whose digits have a product of 10.