Q: How many of the integers between 9 and 19 are divisible by 5?

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19 of them.

There are 19 integers between 1 and 100 containing a 5.

The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.

17, 19, 21

The sum is 3640.

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19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.

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Select all the numbers that $4221462$ is divisible by.

19 of them.

There are 19 integers between 1 and 100 containing a 5.

20 if you include 100, 19 if you don't.

32 of them.32 of them.32 of them.32 of them.

The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.

18 and 19

17, 19, 21

The sum is 3640.

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