19 of them.
There are 19 integers between 1 and 100 containing a 5.
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
The sum is 3640.
17, 19, 21
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
7
Select all the numbers that $4221462$ is divisible by.
19 of them.
There are 19 integers between 1 and 100 containing a 5.
20 if you include 100, 19 if you don't.
32 of them.32 of them.32 of them.32 of them.
The first 3 digit number divisible by 19 is 114 (= 19 x 6) The last 3 digit number divisible by 19 is 988 (= 19 x 52) That means that there are 52 - 6 + 1 = 47 three digit numbers that are divisible by 19.
18 and 19
The sum is 3640.
17, 19, 21
19 numbers.