One thousand of them.
99 hundreds, 10 tens,4 ones
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
ones 5 hundreds is 7 hundreds, thanks now, bye
9
there's only 9 ones whatever is over number 10 is in tens whatever is over 100 is in hundreds
"The hundreds and the ones are the same digit and their sum is 10" did you say ?Well then, the hundreds and ones digit are both 5.And the tens is 2 less than that, or 3.So the number is . . . . . 535
To write 10 hundreds plus 10 tens plus 10 ones in standard form, you would add the respective values together. The value of 10 hundreds is 1000, the value of 10 tens is 100, and the value of 10 ones is 10. Adding these values gives us a total of 1110 in standard form.
There are 0.06 of them.
Zero ones.
Fifty thousand.
4
There are 800 ones in 800. In the base-10 number system, each place value represents a power of 10, so the digit 8 in 800 represents 8 hundreds, or 800 ones.