Infinitely many, starting with:
6 + 6 = 12
8 + 4 = 12
10 + 2 = 12
12 + 0 = 12
14 + (-2) = 12
16 + (-4) = 12
...
100
There are two pairs of even numbers that satisfy the condition. They are (8, 10) and (6, 12).
-- There are 11 even numbers that are less than 1/2 of 46. -- Each of those can be paired with another even number that is more than 1/2 of 46. -- So there are 11 possibilities.
Y is the second number in a set of ordered pairs.
I think of factor pairs of 24, like 8 and 3, that add up to 11.
100
There are two pairs of even numbers that satisfy the condition. They are (8, 10) and (6, 12).
If you include negative numbers, the list is infinite.
no
-- There are 11 even numbers that are less than 1/2 of 46. -- Each of those can be paired with another even number that is more than 1/2 of 46. -- So there are 11 possibilities.
-3 + -3 12 + -18
Factor pairs for 18 include 1&18, 2&9, and 3&6. Only one of these pairs adds up to 11.
Y is the second number in a set of ordered pairs.
You can 'factor' a number to find the numbers whose products make that number.
I think of factor pairs of 24, like 8 and 3, that add up to 11.
assuming you want only positive numbers 2+10 4+8 6+6
Infinitely many. However, if you don't want negative numbers, the lower of the two numbers must be at least 0, and at most 22. The higher of the two numbers, of course, will be 46 minus the first number. Perhaps you can work it out from there.