100
2 + 164 + 146 + 128 + 104 pairs of even numbers can be found whose sum is eighteen.
-- There are 11 even numbers that are less than 1/2 of 46. -- Each of those can be paired with another even number that is more than 1/2 of 46. -- So there are 11 possibilities.
Y is the second number in a set of ordered pairs.
I think of factor pairs of 24, like 8 and 3, that add up to 11.
100
2 + 164 + 146 + 128 + 104 pairs of even numbers can be found whose sum is eighteen.
If you include negative numbers, the list is infinite.
no
-- There are 11 even numbers that are less than 1/2 of 46. -- Each of those can be paired with another even number that is more than 1/2 of 46. -- So there are 11 possibilities.
-3 + -3 12 + -18
Factor pairs for 18 include 1&18, 2&9, and 3&6. Only one of these pairs adds up to 11.
Y is the second number in a set of ordered pairs.
You can 'factor' a number to find the numbers whose products make that number.
I think of factor pairs of 24, like 8 and 3, that add up to 11.
assuming you want only positive numbers 2+10 4+8 6+6
The sum of two evens is even so the sum of any number of evens is even. It is, therefore, impossible for the sum of three even numbers, whether or not consecutive, to be 57, which is an odd number.