There are 6.
120
3x2x1=6 permutations.
6! Six factorial. 6 * 5 * 4 * 3 * 2 = 720 =====
There are 6! = 720 permutations.
Permutations = 4 x 3 x 2 = 24Combinations = (4 x 3 x 2) / (3 x 2 x 1) = 24/6 = 6
6
bety beyt btey btye byet byte total 6 permutations for b then repeat for other 3 letters so all 4 letters is 6 x 4 = 24
The word "noon" consists of 4 letters, where 'n' appears twice and 'o' appears twice. To find the number of distinct permutations, we use the formula for permutations of multiset: ( \frac{n!}{n_1! \cdot n_2!} ), where ( n ) is the total number of letters and ( n_1, n_2 ) are the frequencies of the repeating letters. Thus, the number of permutations is ( \frac{4!}{2! \cdot 2!} = \frac{24}{4} = 6 ). Therefore, there are 6 distinct permutations of the letters in the word "noon."
There are 8P5 = 8*7*6*5*4 = 6720
6 of them. 4C2 = 4!/(2!*2!) = 4*3/(2*1) = 6
UNITED = 6 letters The letters in the word UNITED did not repeat so the number of permutations = 6! = 6x5x4x3x2 =720
6! = 6*5*4*3*2*1 = 720