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The first part is easy to work out. Each letter can be one of 26. Thus there are 263 possibilities:

263 = 17,576

For the numbers, there are 9 options for the first digit (0 not allowed) then 9 options for the second digit (the first digit not allowed) then 8 options for the third digit (the first two digits not allowed). Thus there are 9x9x8 = 648

To find out the total number of possibilities for combining these elements, you just multiply the numbers together:

17,576 x 648 = 11,389,248

And so there are just over 11 million different plates that can be formed.

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Q: How many plate number can be formed consisting of 3 letters in the English alphabet and 3 - digit number no using zero sa first digit and without repetition?
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