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That's simple enough. Just count the numbers from 0 to 999,999 and you will find there are one million of them.

Q: How many possible combinations are there using 6 digits from 0 to 9 beginning with any digit and repeating any digit ie commencing with 000000 and ending with 999999?

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There are twelve possible solutions using the rule you stated.

11

120 different combinations (5 x 4 x 3 x 2).

If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.

its 4 possible combinations HA HA HA buy

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There are only five combinations: 1234, 1235, 1245, 1345 and 2345.

pls i need the formular of national game lotto

With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753

There are twelve possible solutions using the rule you stated.

140 possible combinations

120 different combinations (5 x 4 x 3 x 2).

11

If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.

There are millions of possible combinations.

No, it is not possible.

2^n possible combinations

There are only six combinations using you rule. They are:- 235, 237, 325, 327, 723 and 725