There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
12345 but if you can use a decimal, then 0.1234 would be the smallest possible number.
If repeats are allowed than an infinite number of combinations is possible.
The greatest possible number is 888... (repeating).
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
There are twelve possible solutions using the rule you stated.
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With repeating digits, there are 33 = 27 possible combinations.Without repeating any digits, there are 6 combinations:357375537573735753
9,876,543
4321
987654321
10234567
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
120 different combinations (5 x 4 x 3 x 2).
The least possible integer is -98765432. The least possible positive integer is 10234567.
The number of combinations, denoted by 11C6 is 11!/[6!*(11-6)!] = 11*10*9*8*7/(5*4*3*2*1) = 462
There are 10C3 = 10*9*8/(3*2*1) = 120 combinations.