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13 x 12 x 11 x 49 x 48

13 x 12 x 11 because there are 13 possible cards for any given suit, then 12 more of the same suit, then 11 more for the same suit.

At this point, you have 49 cards left, then 48.

So there are 4,036,032 possible hands like that.

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Q: How many possible hands are there for getting 3 Cards of the same suit and 2 random cards?
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