Best Answer

105 or 100,000

Q: How many samples of size 5 are possible when selecting from a set of 10 distinct integers if the sampling is done with replacement?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

If they can be same 15*15 =225 if they have to be distinct 13*17 =221

It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.

The largest possible values for the integers are 47, 49, and 51.

At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.

If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.

Related questions

If they can be same 15*15 =225 if they have to be distinct 13*17 =221

It is not. There are only two possible outcomes for each toss of a coin whereas the number of possible outcomes when selecting a marble from a bag will depend on the numbers of distinct marbles in each bag. The coin toss generates a binomial distribution the marbles experiment is multinomial.

The largest possible values for the integers are 47, 49, and 51.

At least the following families: all integers; all positive integers; all odd integers; and all "square integers", that is, integers that are squares of other integers.

If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.If they are integers, then the possible answers are {1, 6, 8} and {2, 4, 9}.If not, there are infinitely many possible solutions.

yes and it is possible to do

490.

Because with replacement, the total number of possible outcomes - the denominator of the probability ratio - remains the same. Without replacement the number of possible outcomes becomes smaller.

median = 100, mean = 1000 set of numbers = {a,b,100,c,d} a+b+100+c+d = 5000 As the set contains distinct numbers, and there is no range that is given in the problem, we can consider the set of numbers as {1,2,100,101,4796} So the largest possible integer can be 4796.

Not possible in consecutive integers, nearest is consecutive even integers: 148 & 152

If I understand your question, the answer is 'no', because all integers are rational numbers.

In every possible way- because whole numbers and integers are the same.