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Q: How many sides do 2 quadrilaterals and 3 pentagons have altogether?

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37 sides

A pentagon has five sides, and a quadrilateral has four sides. So five pentagons and three quadrilaterals have 5*5 + 3*4 sides = 25 + 12 sides = 37 sides.

They add up to (1*10)+(4*4)+(3*5) = 41 sides altogether

A pentagon has five sides, and a decagon has ten sides. So 3 pentagons and 5 decagons have (35)+(510) = 65 sides altogether

A pentagon has fives sides, and a quadrilateral has four. So 2 pentagons and 1 quadrilateral have 2*5 + 4 = 10 + 4 = 14 sides altogether.

A heptagon has seven sides and a pentagon has five. So 2 heptagons and 2 pentagons have 2*7 + 2*5 = 14 + 10 = 24 sides altogether.

A dodecagon has 12 sides, and a quadrilateral has 4 sides, so 3 dodecagons and 2 quadrilaterals have 3*12 + 2*4 = 36 + 8 = 44 sides altogether.

A dodecagon has 12 sides, and a quadrilateral has 4. So in 2 dodecagons and 4 quadrilaterals there are 2*12 + 4*4 = 24 + 16 = 40 sides altogether.

A heptagon has seven sides and a quadrilateral has four, so 1 heptagon and 3 quadrilaterals have 1*7 + 3*4 = 7 + 12 = 19 sides altogether.

heptagons have 7 sides pentagons have 5 sides therefore 4 x 7 = 28 4 x 5 = 20 Total 48 sides.

A decagon has 10 sides, a dodecagon 12, and a pentagon 5. So 4 decagons, 5 dodecagons, and 3 pentagons have 4*10 + 5*12 + 3*5 sides = 40 + 60 + 15 = 115 sides altogether.

Altogether there are: (5*5)+(3*6)+(1*8) = 51 sides

There are six sides in a hexagon, five in a pentagon, and three in a triangle. So in 2 hexagons, 2 pentagons, and 1 triangle there are 2*6 + 2*5 + 1*3 = 12 + 10 + 3 = 25 sides altogether.

A dodecagon has 12 sides, and a pentagon has 5 sides. So 5 dodecagons have 5*12 = 60 sides, and 4 pentagons have 4 * 5 = 20 sides, for a total of 60 + 20 = 80 sides.

1*12 + 3*4 = 12 + 12 = 24

There are infinitely many polygons which have this property. The easiest to think of is a right triangle. But there are also quadrilaterals, pentagons, etc., that can be constructed that have this property.

A heptagon has seven sides, a nonagon has nine, and a quadrilateral has four. So in 2 heptagons, 3 nonagons, and 3 quadrilaterals there are: (2*7)+(3*9)+(3*4) = 14 + 27 + 12 = 53 sides altogether.

There are 12 sides in a dodecagon, 4 in a quadrilateral, and 3 in a triangle. So in 4 dodecagons, 4 quadrilaterals, and 4 triangles there are 4*12 + 4*4 + 4*3 = 48 + 16 + 12 = 76 sides altogether.

There are 11 times 5 = 55 sides in 11 pentagons.

1 pentagon = 5 sides. 55 pentagons = 5*55 = 275 sides.

A hexagon has six sides, and a nonagon has nine. Three hexagons and three nonagons then have (3 x 6) + (3 x 9) = 18 + 27 = 45 sides altogether.

15

A pentagon has 5 sides. If you have 4 pentagons, you use: 4x5=20. Therefore, 4 seperate pentagons have 20 sides. This is not true if you have them combined however.

20 :)

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