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The sum of the interior angles of a polygon wit n sides is (n-2)*180 degrees.

So (n-2)*180 = 3960

Dividing both sides by 180 gives: (n-2) = 22 so that n = 24.

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How many sides a polygon have if the sum of the measures of the interior angles is 3960?

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How many sides does a polygon have if the sum of the measures of the interior angles in 3960?

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How many sides does a polygon have if the sum of the measures of the interior angles is 3960 degress?

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To find the measure of each interior angle in a polygon when the sum of the angles is given, you divide the total sum by the number of angles in the polygon. If the sum of the interior angles is 3960, and the polygon is a hexagon (6 sides), each interior angle would measure 660 degrees (3960 ÷ 6 = 660). This is because the sum of the interior angles of a polygon with n sides is given by (n-2) * 180 degrees.


How many sides would a polygon have if the measure of the interior angles is 3960 degrees?

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What are the sum of the interior angles of a 24-gon?

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Any measure you like. The only constraint is that the sum of all the interior angles - which can all be different - is 3960 degrees.


What is the sum of the interior angles in a 24 sided shape?

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How many sides does a polygon have if the sum of the measure of the interior angle is 3960?

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What is the sum of the interior angles of 24-gon?

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