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How many sides does a regular poloygon have if each exterior angle is 18 degrees?
Wiki User
∙ 14y ago
measure of each interior angle = 360 - m of each exterior angle
m each i. angle = 360 - 18 = 342
let n be the no. of sides and thus also the no. of interior angles
(n-2)180 = 342(n)
180n - 360 = 342n
-360 = 162n
n = - 360
---------
162
polygon does not exist
Wiki User
∙ 14y ago
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