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How many sides would a regular polygon have if one of its exterior angles measures X and one of its interior angles measures 3X?
Wiki User
∙ 14y ago
180 degrees on a straight line.
3x+x = 180
4x = 180
x = 45
Therefore: one interior angle is 135 degrees and one exterior angle is 45 degrees.
Total sum of exterior angles of any polygon is 360 degrees.
360/45 = 8
It will be a regular octagon that has 8 equal sides.
Wiki User
∙ 14y ago
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One exterior angle of a regular polygon measures 36 What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 36. What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 30 degrees what is the sum of the polygon's interior angle measures?
1800 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What is the sum of the measures of the interior angles of the regular polygon if each exterior measures 120?
Hint: in a regular polygon interior plus exterior = 180o, always.
One exterior angle of a regular polygon measures 40 What is the sum of the polygon's interior angle measures?
1260
What is the sum of the measures of the interior of a regular polygon if each exterior angle measures 90?
360
One exterior angle of a regular polygon measures 36 What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 36. What is the sum of the polygon's interior angle measures?
1440 degrees
One exterior angle of a regular polygon measures 30 degrees what is the sum of the polygon's interior angle measures?
1800 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 90?
360
What is the sum of the measures of the interior angles of a regular of a regular polygon if each exterior angle measures 120?
If exterior angles are 120 then interior angles must be 60 so you have an equilateral triangle
What is the measures of the interior angles of a regular polygon if each exterior angle measures 72?
The interior angle of any regular polygon can be calculated using the formula 180 * (n - 2) / n, where n is the number of sides. In this case, since each exterior angle measures 72 degrees, the interior angle would be 180 - 72 = 108 degrees. So the measures of the interior angles in this regular polygon would be 108 degrees.
What is the sum of the polygon's interior angle measures if the exterior angle of a regular polygon's 36 degree?
1440 degrees
What is the sum of the measures of the interior angles of a regular polygon if each exterior angle measures 72?
540 degrees
What is the measures of an interior angle and an exterior angle of a regular polygon with 6 sides?
Interior angle = 120 degrees Exterior angle = 60 degrees
