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A chemist requires 0.277 mol Na2CO3 for a reaction. How many grams does this correspond to?
The molar mass of Na2CO3 is 105.99 g/mol. To find the mass corresponding to 0.277 mol, you would multiply the molar mass by the number of moles: 0.277 mol x 105.99 g/mol = 29.36 grams.
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
To convert moles to grams, you need to use the molar mass of magnesium fluoride, which is 62.301 grams/mol. Thus, 4.78 moles of magnesium fluoride would be 4.78 moles * 62.301 grams/mol = 298.06 grams of magnesium fluoride.
How many grams are in one mole of water using 4 significant figures?
The molar mass of water is approximately 18.02 g/mol. Therefore, one mole of water would weigh approximately 18.02 grams, considering 4 significant figures.
How many moles in 10g of iodine?
To calculate the number of moles in 10g of iodine, you need to first determine the molar mass of iodine (I), which is 126.9 g/mol. Then, you can use the formula: moles = mass / molar mass. So, moles = 10g / 126.9 g/mol ≈ 0.079 moles of iodine.
How many moles of KCl are contained in 1.9L of a 0.90M KCl solution three significant figures please?
The number of moles of KCl can be calculated by multiplying the volume of the solution in liters by the molarity of KCl. This results in 1.9 L * 0.90 mol/L = 1.71 mol of KCl in 1.9 L of a 0.90 M KCl solution.
How many significant figures are in 6.022 x 10 23 atoms Per mol?
4 of them.
Yonas has 44.78 g of cupric sulfate. How many moles does he have?
Cupric sulfate is CuSO4 which has a molar mass of 159.6g/mol. Thus 44.78 g x 1 mol/159.6 g = 0.2806 moles (to 4 significant figures).
Calculate the number of moles in 52g of Be?
52 g Be x 1 mol/9 g = 5.8 moles (2 significant figures)
How many grams is contained in .27 moles of calcium?
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
A chemist requires 0.277 mol Na2CO3 for a reaction. How many grams does this correspond to?
The molar mass of Na2CO3 is 105.99 g/mol. To find the mass corresponding to 0.277 mol, you would multiply the molar mass by the number of moles: 0.277 mol x 105.99 g/mol = 29.36 grams.
What is the molarity of a solution that contains 0.65 moles of NaNO3 in 250 mL of solution?
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
How many moles per mL of the solute are contained in the 0.20 M NaCl?
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
To convert moles to grams, you need to use the molar mass of magnesium fluoride, which is 62.301 grams/mol. Thus, 4.78 moles of magnesium fluoride would be 4.78 moles * 62.301 grams/mol = 298.06 grams of magnesium fluoride.
Determine the molarity of a solution formed by dissolving 97.7 g LiBr in enough water to yield 750.0 mL of solution?
Molarity = moles of solute / total volume of solution (L or dm3) Moles LiBr = 97.7 g / (6.94 + 79.9) g mol-1 =1.13 mol M = n / V = 1.13 mol / 0.7500 L = 1.50 M There are only three significant figures in the mass of the solute but four in the volume, therefore, answer can not be more than three significant figures.
The molar mass of NaCO3 to four significant figures is what not inscientific notation?
The formula is either:Na2CO3 (sodium carbonate) with molar mass 105.9884 g/mol (anhydrous),orNaHCO3 (sodium bicarbonate) with molar mass 84.01 g/mol,butNaCO3 doesn't exist.
How many atoms are in 6.45 mol of silicon?
There are 3.89 x 10^24 atoms in 6.45 mol of silicon. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of moles of silicon.
