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A chemist requires 0.277 mol Na2CO3 for a reaction. How many grams does this correspond to?
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
How many grams are in one mole of water using 4 significant figures?
1 mole H2O = 18.02g --- water is H2O ... 2 x 1.008 + 1 x 15.996 = 18.012 g/mole = 18.01 grams
How many moles in 10g of iodine?
To calculate the number of moles in 10g of iodine, you need to first determine the molar mass of iodine (I), which is 126.9 g/mol. Then, you can use the formula: moles = mass / molar mass. So, moles = 10g / 126.9 g/mol ≈ 0.079 moles of iodine.
How many moles of KCl are contained in 1.9L of a 0.90M KCl solution three significant figures please?
The number of moles of KCl can be calculated by multiplying the volume of the solution in liters by the molarity of KCl. This results in 1.9 L * 0.90 mol/L = 1.71 mol of KCl in 1.9 L of a 0.90 M KCl solution.
How many significant figures are in 6.022 x 10 23 atoms Per mol?
4 of them.
Yonas has 44.78 g of cupric sulfate. How many moles does he have?
Cupric sulfate is CuSO4 which has a molar mass of 159.6g/mol. Thus 44.78 g x 1 mol/159.6 g = 0.2806 moles (to 4 significant figures).
How many grams is contained in .27 moles of calcium?
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
Calculate the number of moles in 52g of Be?
52 g Be x 1 mol/9 g = 5.8 moles (2 significant figures)
What is the molar mass of aluminum to 10 significant figures?
The molar mass of aluminum is approximately 26.9815385 grams per mole (g/mol) when expressed to ten significant figures. This value is derived from the atomic mass of aluminum as found on the periodic table.
A chemist requires 0.277 mol Na2CO3 for a reaction. How many grams does this correspond to?
0.277 mole Na2CO3 x 106 g/mole = 29.4 g (to 3 significant figures)
How many grams of potassium are there in 7.20 mol of potassium atoms?
7.20 moles K x 39.1 g/mole = 281.52 g K = 282 g K (to 3 significant figures)
What is the molarity of a solution that contains 0.65 moles of NaNO3 in 250 mL of solution?
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
How many moles per mL of the solute are contained in the 0.20 M NaCl?
0.0002 mol NaCl/mLmolarity = (moles solute)/(L of solution)0.20 M NaCl = 0.20 mol NaCl/L1 L = 1000 mL0.20 mole NaCl/1000 mL = 0.00020 mol NaCl/mL (rounded to two significant figures)
How many GRAMS of magnesium fluoride are present in 4.78 moles of this compound?
The formula unit for magnesium fluoride is MgF2. From the periodic table, add the atomic weight of 1 magnesium atom and 2 fluorine atoms to get to get 62.3018. This means that 1 mole of MgF2 is 62.3018g of MgF2. Now, to find out the mass of 4.78 mol MgF2 X the g/mol so that you will cancel the moles, and keep the grams. 4.78 mol MgF2 X 62.3018g MgF2/1mol MgF2 = 297g MgF2 *The answer 297 is in keeping with significant figures. When you multiply or divide, the answer can have no more than the fewest significant figures in the calculation, which was 4.78, and which has only three significant figures.
Determine the molarity of a solution formed by dissolving 97.7 g LiBr in enough water to yield 750.0 mL of solution?
Molarity = moles of solute / total volume of solution (L or dm3) Moles LiBr = 97.7 g / (6.94 + 79.9) g mol-1 =1.13 mol M = n / V = 1.13 mol / 0.7500 L = 1.50 M There are only three significant figures in the mass of the solute but four in the volume, therefore, answer can not be more than three significant figures.
The molar mass of NaCO3 to four significant figures is what not inscientific notation?
The formula is either:Na2CO3 (sodium carbonate) with molar mass 105.9884 g/mol (anhydrous),orNaHCO3 (sodium bicarbonate) with molar mass 84.01 g/mol,butNaCO3 doesn't exist.
