3 significant figures.
4 of them.
Four
45.0300mm has six significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.
There are 25.4 millimetres in one inch. 65/25.4 = 2.5590551181102, or 2.6 inches to the correct significant figures.
There are 25.4 millimetres in one inch. Therefore, rounded to three significant figures, 0.34 millimetres is equal to 0.34/25.4 = 0.0134 inches. Direct Conversion Formula 0.34 mm* 1 in 25.4 mm = 0.01338582677 in
both 40 and 400 have one because there is no "." the 0.7000 has four SF because you know that the first three digits after the seven are exact while the last zero could be rounded. the concept is a little tough to get but once you do its pretty simple.
1in = 2.54cm 1cm = 10mm 550mm x 1cm/10mm = 55cm 55cm x 2.54cm/1in = 140in (Rounded to two significant figures.) Direct Conversion Formula 550 mm* 1 in 25.4 mm = 21.65354331 in
2 significant figures.
There are 6 significant figures in this length.
There are 3 significant figures in this number.
It has 2 significant figures. However, the fact that it is given as 2300 mm and not as 230 cm suggests that it is, in fact significant to 4 figures.
4
2 of them.
4. The zeroes to the left are not significant, the zero to the right, is.
111.009 mm rounded off to four significant figures is 111.0
3 of them.
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
110.1mm
45.0300mm has six significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.