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How many significant figures will the product of 0.1400 and 6.02 and 1023 have?
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What is the value of avogadro's number to 4 significant figures in terms of the mole?
6.022 x 1023
What it the total number of atoms in one molicule in carbon dioxide?
1 mole C = 12.011g C 1.2g C x 1mol C/12.011g C = 0.10 mole C rounded to two significant figures
How many moles are 3.58 x 1024 atoms of pure uranium 5.95 mole U?
3.58 X 1024 atoms of uranium (1 mole U/6.022 X 1023) = 5.94 moles uranium to be precise and with significant figures -------------------------------------------------------------------------------
What is the volume of the planet Mercury given that it has a mass of 3.302 x 1023 kg and a density of 5.43 x 103 kg m-3 Give answer to the appropriate no of significant figures and correct SI units?
6.08 x 1019 kg m 3
How many atoms are in 30 moles of iron?
A mole is 6.022×1023 of anything, including atoms. So to determine the number of atoms are in 30 moles of iron, you multiply the number of moles times 6.022×1023. 30mol Fe x 6.022×1023 atoms Fe/1mol Fe = 1.8066×1025atoms Fe When corrected for significant figures, the answer is 2×1025atoms Fe. Note: the number following the 10 in the large numbers is the exponent on the 10 and should be written as superscripts, but that is not supported at the moment.
What is the value of avogadro's number to 4 significant figures in terms of the mole?
6.022 x 1023
How many twelve are there in the product of 1023 and 24?
There are: (1023*24)/12 = 2046
How many grams are there in 3.3 x 1023 molecules of N2I6?
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
What name is given to the number 6.02 times 1023?
The product of 6.02 and 1023 is 6158.46
How many significant digits are there in 6.023 1023 molecules?
8
How many grams are in 8.2 x 1022 molecules of NCl3?
1 mole NCl3 = 120.366g NCl3 = 6.022 x 1023 molecules NCl3 8.2 x 1022 molecules NCl3 x 120.366g NCl3/6.022 x 1023 molecules NCl3 = 16g NCl3 rounded to 2 significant figures
How many twelves are there in the product of 1023 TIMES 24?
2406
How many moles are there in 5.5x0x1o23 atoms?
Since the product of zero with any other number(s) is zero, there are no moles in the question as written. If 5.5 X 1023 was intended to be written instead of "5.5x0x1o23", the answer is (5.5 X 1023 )/(Avogadro's number) = 0.83 moles, to the justified number of significant digits.
What it the total number of atoms in one molicule in carbon dioxide?
1 mole C = 12.011g C 1.2g C x 1mol C/12.011g C = 0.10 mole C rounded to two significant figures
What is the product of 27 and 10 to the power of 23?
27 x 1023 = 2700000000000000000000000
How many moles are 3.58 x 1024 atoms of pure uranium 5.95 mole U?
3.58 X 1024 atoms of uranium (1 mole U/6.022 X 1023) = 5.94 moles uranium to be precise and with significant figures -------------------------------------------------------------------------------
What is the volume of the planet Mercury given that it has a mass of 3.302 x 1023 kg and a density of 5.43 x 103 kg m-3 Give answer to the appropriate no of significant figures and correct SI units?
6.08 x 1019 kg m 3
