figure it out then tell me :)
32C3 = 4960
The number 30 is "thirty" and 31 is "thirty-one."
Thirty-five hundredths in number form is 0.35
As a number: 38,000,000,000
24
one and thirty-one. It is a prime number.
That would be the number of possible combinations of men, multiplied by the number of possible combinations of men. For each subset, the total number of possible combinations will be the factorial of the number available, divided by the factorial of that number minus six. In other words:x = 10!/(10 - 6)! * 12!/(12-6)!∴ x = 10!/4! * 12!/6!∴ x = (10 * 9 * 8 * 7 * 6 * 5) * (12 * 11 * 10 * 9 * 8 * 7)∴ x = 151200 * 665280∴ x = 100590336000So there are one hundred billion, five-hundred-and-ninety million, three-hundred-and-thirty-six thousand possible jury combinations from that selection.
0.935
Yes because compsite numbers are not 1 or 0!
Even numbers are divisible by 2, and odd numbers are not. 36/2=18, so 36 is an even number.
All of these numbers are prime numbers that are less than thirty: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29
I assume you mean "six numbers" rather than "sox numbers". If the numbers are all distinct (i.e none of them are in the set of thirty numbers more than once), then there are 30!/(24!6!) ways of choosing six numbers, where "!" is the factorial of that number.