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Let's look at this digit-by-digit:

The first digit can be any number 1-9: 9 choices

The second digit can be any number 1-9 except the one that the first digit is: 8 choices

The third digit can be any number 1-9 except the ones chosen by the first and second digits: 7 choices

9*8*7 = 504 total numbers

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Q: How many three digit numbers can be formed that do not contain the number zero and no number can repeat?
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