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From Rafaelrz,

The number of three digit permutations you can get from the four different digits

3. 6. 7. 9, is given by:

4P3 = 4!/(4-3)! = 4x3x2x1/1 = 24

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Q: How many three digit numbers can you make using 3 6 7 9 using each digit only once in every number?
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