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Q: What is the smallest three-digit number divisible by the first three prime numbers and the first three composite numbers?

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12

45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.

Yes. 120 is composite. It is divisible by other numbers than 1 and itself, such as 2, 3, and 20.

The smallest number that can be divisible by these three numbers is 42. If 42 is multiplied by 2, 3, 7, or any number divisible by only one of those numbers then that number as well will be divisible by 2, 3, and 7.

13

Related questions

4 is the smallest composite number and it is not divisible by the two given numbers.

If it is a composite number, it is divisible by at least one prime number.

2310

It is 2520.

2520

Composite numbers are divisible by prime numbers.

Smallest composite number dividable by prime numbers is product of them all. In this case it is: 2x3x5x7x11 = 2310.

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

The answer is Composite numbers are evenly divisible by their factors.

None. 12 is a composite and any number divisible by a composite is itself a composite.

Composite numbers are numbers that are not prime- that is, they are divisible by numbers besides 1 and themselves. 51 is actually divisible by 1, 3, 17, and 51, so it is composite.

120

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