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The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.

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Q: What is the smallest three-digit number divisible by the first three prime numbers and the first three composite numbers?

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12

45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.

Yes. 120 is composite. It is divisible by other numbers than 1 and itself, such as 2, 3, and 20.

The smallest number that can be divisible by these three numbers is 42. If 42 is multiplied by 2, 3, 7, or any number divisible by only one of those numbers then that number as well will be divisible by 2, 3, and 7.

The four smallest three digit composite numbers are: 100, 102, 104, 105 with sum 411.

Related questions

4 is the smallest composite number and it is not divisible by the two given numbers.

If it is a composite number, it is divisible by at least one prime number.

2310

2520

It is 2520.

Smallest composite number dividable by prime numbers is product of them all. In this case it is: 2x3x5x7x11 = 2310.

the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.

The smallest number that is both odd and composite is 9, which is divisible by 3. The odd numbers are 1, 3, 5, 7, 9, 11, ..., and 1, 3, 5, and 7 are all prime. It is 9 that is the smallest odd composite number.

120

None. 12 is a composite and any number divisible by a composite is itself a composite.

Composite, even numbers are divisible by two

Both composite 75 is divisible by 5 112 is divisible by 2 ... and other numbers