90 divided by 9 is 10
so you can subtract 9 from 90 for 10 times before you reach 0
if you want to go into negative numbers you can keep subtracting as many times as you like
you are sooooooooo wrong WOW. You can subtract 9 once from 90 because once you subtract 9 from 90, 90 becomes 81. That's how I do it
Wiki User
โ 14y agoInfinitely many times; you can always subtract 2 from whatever number you have in the series 9 - 2n.
90 divided by 10 is 9, so 10 goes into 90 9 times.
39 / 9 = 4 + 1/3 So 9 can be subtracted from 39 4 times.
10*9=90
First, we can truncate the .00 off of the 90.00 to just make 90 for simplicity. Next, we take .10*90, which is 9. Subtract that from your original number, 90. 90-9=81. There is another way to do this problem. First, we have 100 percent, or 1. Next, we subtract 10 percent from that, or .1. 1-.1=.9, so we multiply .9*90=81.
Infinitely many times; you can always subtract 2 from whatever number you have in the series 9 - 2n.
The answer is 9 times 9 + x = 90 9+881 =90 81/9 =9 So 90 is greater than 9 by 9 times.
99
90 divided by 10 is 9, so 10 goes into 90 9 times.
9 times
81/90 - 40/90 = 41/90
90 รท 9 = 10
90
39 / 9 = 4 + 1/3 So 9 can be subtracted from 39 4 times.
Exactly 10 times
9 times with a remainder of 10
9 times