Infinitely many times; you can always subtract 2 from whatever number you have in the series 9 - 2n.
90 divided by 9 is 10 so you can subtract 9 from 90 for 10 times before you reach 0 if you want to go into negative numbers you can keep subtracting as many times as you like you are sooooooooo wrong WOW. You can subtract 9 once from 90 because once you subtract 9 from 90, 90 becomes 81. That's how I do it
39*9=351
4 with 3 remaining 39 - 3 = 36 = 9 x 4
To determine how many times 4 will go into 39, we divide 39 by 4. The result is 9 with a remainder of 3. Therefore, 4 will go into 39 nine times with a remainder of 3.
Infinitely many times; you can always subtract 2 from whatever number you have in the series 9 - 2n.
90 divided by 9 is 10 so you can subtract 9 from 90 for 10 times before you reach 0 if you want to go into negative numbers you can keep subtracting as many times as you like you are sooooooooo wrong WOW. You can subtract 9 once from 90 because once you subtract 9 from 90, 90 becomes 81. That's how I do it
4 times, remainder 3
39*9=351
First you multiply 4 and 9, which you get 36 then you add the 3, which makes 39 and then subtract 6... leaving you with an answer of 33. :)
4 with 3 remaining 39 - 3 = 36 = 9 x 4
To determine how many times 4 will go into 39, we divide 39 by 4. The result is 9 with a remainder of 3. Therefore, 4 will go into 39 nine times with a remainder of 3.
9 times with a remainder of 31
351
13 goes into 516 39 times, with a remainder of 9.
9 whole times, plus 3/4 of one more time.
Original Equation: 4x + 9x = 39 Factor: x(4+9) = 39 Add: x(13) = 39 Divide: x = 3 Check: 4(3) + 9(3) = 12 + 27 = 39 = 39