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If you mean: 3x2+8+5 = 0

Then it crosses the x axis at points -1 and -5/3

Q: How many times does 3x2 plus 8x plus 5 touch or cross the x axis?

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It will touch it once.

Once.

Once and the roots are said to be equal.

y=1 does not cross the x-axis. It is a line parallel to the x-axis (and therefore can't ever cross it)

A graph of an equation in the form y = ax^2 + bx + c will cross the y-axis once - whatever its discriminant may be.

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It will cross the x-axis twice.

It would not touch or intersect the x-axis at all.

It will touch it once.

Once.

Once and the roots are said to be equal.

It doesn't cross the x-axis since the position the equation is in is 9 units above the x-axis and the graph never curves the other way so it will never touch the x-axis

y=1 does not cross the x-axis. It is a line parallel to the x-axis (and therefore can't ever cross it)

A graph of an equation in the form y = ax^2 + bx + c will cross the y-axis once - whatever its discriminant may be.

Without knowing the plus or minus value of 40 it's difficult to say but in general:- If the discriminant of a quadratic equation = 0 then it touches the x axis at 1 point If the discriminant is greater than zero then it touches the x axis at 2 points If the discriminant is less than zero then it does not touch the x axis

It will touch it at exactly 1 point. If a quadratic function is given as f(x) = ax2 + bx + c, let the discriminant be denoted as D. Then the graph of y = f(x) will cross the x-axis at the x-values x = (-b + sqrt(D))/(2a) and x = (-b - sqrt(D))/(2a). When the discriminant D = 0, these 2 x-values are actually the same. Thus the graph will touch the x-axis only once.

Discriminant = 116; Graph crosses the x-axis two times

0 real solutions. There are other solutions in the complex planes (with i, the imaginary number), but there are no real solutions.