That happens ten times in a 12-hour period.
36 times
During the last second of every hour = 23 times.
The amount of times 3 digits of the same number appear in a 24 hour span is 32. Do the math...figure it out.. :D Enjoy!
36 times. Hint: Seven, eight and nine can all be discarded.
386 times
36 times
36 times
During the last second of every hour = 23 times.
Four.
The amount of times 3 digits of the same number appear in a 24 hour span is 32. Do the math...figure it out.. :D Enjoy!
36 times. Hint: Seven, eight and nine can all be discarded.
The answer is 65. Start with 1:23, 1:24, 1:25, etc. Do this for each hour. Don't for get the 12th hour....12:34......etc
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386 times
An hour has 60 min. Assuming the clock has only the hour and minute displayed, every hour 1 would appear at 1, 11,12,13,14,15,16,17,18,19,10,21,31,41,51. Counting 11 as once there are 15 1s in an hour. In the 24 hours, only 0,2,3,4,5,6,7,8,9,22,23 have no 1 s in them. Therefore 1 aooears 165 times in those times. As for hours 1,10,11,12,13,14,15,16,17,18,19,21, there is always a 1 in the clock. This makes 1 appear 12*60 times which is 720 times. Therefore in total, 1 appears 885 times in a digital 24 hour clock.
Assuming that once a number appears only once even if it remains for an hour - for example, the 5 in the hours place does not disappear and reappear at 5:00, 5:01, 5:02 and so on - it is 170 times over a 24-hour period.
There are four digits on a digital clock. A seven will never appear in two of them. It will appear 6 times per hour (07, 17, 27, 37, 47, 57) and once each at 7 am and 7 pm, or 700 and 1700 if you're keeping military time. My best guess: 24 x 6 + 2 = 144