1 mile = 5,280 ft
1 ft = 12 inches
Circumference of a circle = 2 pi R.
Circumference of the wheel = [ 28 pi ] inches
500 miles = (500 x 5,280 x 12) inches
Number of wheel-circumferences in 500 miles = (500 x 5,280 x 12) / (28 pi) = 360,144.9 revs
Radius of the wheel: 24/2 = 12 inches
If the wheel made 3000 revolutions and covered 45000 pi inches, then one revolution would cover 15 pi inches. That is the circumference. The circumference is equal to 2 times the radius times pi. Then the radius is 7.5 inches.
There are 5280 feet in a mile. Multiply this by 199. Convert those feet to inches and divide by 14.
20 inches will be the 'diameter' so the 'radius' will be 10 inches.
The radius will be half the diameter which is 20/2 = 10 inches
Well, isn't that just a happy little question! If the diameter of the wheel is one yard, which is 36 inches, then the radius would be half of that. So, the radius of the wheel would be 18 inches. Just remember, there are no mistakes, just happy little accidents!
30. The radius is not relevant. Each roll is one revolution.
12 inches
Multiply the radius by 2 x pi.
Radius is 36/2 = 18 inches
If by "27 inch wheel" you mean:"a wheel with a circumference of 27 inches" The answer is 27 inches."a wheel with a radius of 27 inches" The answer is 54π inches"a wheel with a diameter of 27 inches" The answer is 27π inches
The mechanical advantage of a wheel and axle is the ratio of the radius of the wheel to the radius of the axle. Ex:- Suppose the radius of the wheel is four times greater than the radius of the axle, every time you turn the wheel once, your force will be multiplied four times.