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How many unique ways can 13 be obtained from the sum of 6 odd numbers?
Wiki User
∙ 12y ago
None.
The sum of any two odds must be even. The sum of any two evens must be evens so the sum of any number of evens must be even.
So the sum of 6 odds = sum of 3 pairs of evens = ie sum of 3 evens even + even + even = even
13 is odd and the sum of 6 odds is even so there is no way that one can be made the same as the other.
Wiki User
∙ 12y ago
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I count 5, not counting the different orders that they are added as different ways. Here they are. If I missed some, then somebody else can add to it:3 + 3 + 3 + 3 + 1 = 133 + 3 + 5 + 1 + 1 = 135 + 5 + 1 + 1 + 17 + 3 + 1 + 1 + 19 + 1 + 1 + 1 + 1If you want to count different orders as unique, For #1, there are 4 additional ways (I wouldn't say that the different 3's are unique, so the 1 in each position).For #2, I count 13 additional ways. For # 3, I count 8 additional. For #4, I count 7 additional ways. And for #5, I count 4 additional ways. So that would be 36 additional ways, rearranging the orders, for a total of 41 ways.
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