An n-digit number has 4^n such numbers.
The longest string of consecutive numbers that are primes is two digits long, consisting of 2 and 3 only. There are no other consecutive numbers that are primes because no even numbers greater than 2 are primes.
The set of primes would be one. The set of Mersenne primes is another. The set of all primes below 50 is another. And so on. A set which includes all primes, and only them, is the set of numbers having exactly 2 factors.
No, 11 is the only palindromic prime with an even number of digits.
There is only 1 pair of primes and they are 2*5.
2 and 3 are the only consecutive primes.
The only primes in the twenties are 23 and 29.
2 and 3 are the only consecutive numbers that are prime.
500
Yes. The only time this occurs is right at the start of the list of primes: 2, 3.
only one: 2.'2' is the only even prime number. All other even numbers have '2' as a factor.
There are only 2 primes in 80: 2 and 5.
Assuming each of the given digits can be used only once, the answer is 24. If not, the answer is infinity.