How many watts are in a system with 120 v and 25 amps?

Answer 1

The formula you are loking for is W = E xE/R.

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The question is a little vague, but assuming you mean that the 120 volts is measured across the portion of the circuit having the 0.5 ohm resistance, then the answer is 28,800W dissipated in that resistance. The basic formula for power dissipation is current (measured in Amperes) X electromotive force (measured in Volts). We typically write this as P = IV or sometimes P=IE, where P represents power in Watts, I represents current in Amps, and V or E represent electromotive force in Volts. In the example cited in your question, we have the voltage, but we don't have the current. Since we do know the resistance, though, we can calculate the current from ohms law, which states that the voltage will always equal the product of resistance and current. We write this as V = IR, where V and I are voltage and current as above, and R represents resistance in Ohms. We can manipulate this expression to give us the current from voltage and resistance as I = V/R. Now we plug this expression into our power expression by substituting V/R in place of I.

P = IV becomes P = (V/R)V. Which we clean up to get P = V^2/R, where V^2 means the square of the voltage.

So, using this expression for the example we get P = 120*120 / 0.5 = 28,800W. :-)

Answer 2

How many convert 0.5 amp to my electric bill

Answer 3

power = v x I

120 X 25

3000W,

1KW=1000W SO,3000 DIVIDED BY 1000

3000/1000=3KW,IT WILL DRAW 3KW THAT 25AMP 120V CIRCUIT...

Answer 4

The answer is 120 x 12.5 watts. In practice it could be less depending on the power factor.

Answer 5

The equation that you are looking for is W = A x V.

Answer 6

3000 watts