5!= 5*4*3*2*1= 120 ways
8 ways:5 + 79, 11 + 73, 13 + 71, 23 + 61, 31 + 53, 37 + 47, 41 + 43Ignoring the commutative property of addition and considering "5 + 79" different to "79 + 5", a further 8 ways making 16 ways in total are possible by reversing the order of the numbers in each of the above additions.
13 x 13 x 13 = 2197 possible combinations
24 different ways. For each of the four possible first spots, there are three possible second spots, two possible third spots, and then the last spot is the one left over. So there are 4! (four factorial) possible arrangements.
8+6+5--19
there are 5 ways
1.00+25+25+5=1.55 25+25+25+25+25+25+5=1.55 10+10+10+10+10+10+10+10+10+10+10+10+10+10+10+5=1.55 are the possible ways.
120 ways.120 ways.120 ways.120 ways.
50 to 110 500 to 1100 are two possible ways.
9+5-3-5+3=10alternate ways r possible..
1004
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.