Imagine lining 7 people in a row.
You have 7 people to choose from for the first person and 6 people to choose from for the second person and so on and so on , so
answer=7x6x5x4x3x2x1
7 factorial, or 5,040.
5040
The letters in the word can be arranged in 7!/4! = 210 ways if A and a are treated the same. If A and a are considered different (so that, for example, Alabama is not alabAma), then there are 7!/3! = 840 ways.
ANS 420 problem 7!/ (6!*2!)
8! or 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40320
The answer is 7!/5! = 42 ways.
In how many distinct ways can the letters of the word MEDDLES be arranged?
7654321 = 7! = 5,040
7 factorial, or 5,040.
5040
The letters in the word can be arranged in 7!/4! = 210 ways if A and a are treated the same. If A and a are considered different (so that, for example, Alabama is not alabAma), then there are 7!/3! = 840 ways.
ANS 420 problem 7!/ (6!*2!)
If the books have to be the correct way up and spine outwards: 7! ways =7x6x5x4x3x2x1 =5040 ways. If the books can be any way in (upside down, spine inward, etc.): (7!x4^7) ways =7x4x6x4x5x4x4x4x3x4x2x4x1x4 =82,575,360 ways
720
8! or 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 40320
Seven symbols can be arranged in (7 x 6 x 5 x 4 x 3 x 2) = 5,040 ways.
There are eight letters in anaconda, so....,8!Means,8 * 7 * 6 * 5 * 4 * 3 * 2= 40,320 ways===========