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How many ways can I select a committee of 3 people from 10 people?
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How many ways can you select 3 people out of 10?
240
How many ways can a 4 person subcommittee be selected from a committee of 8 people?
There are 8!/(4!*4!) = 70 ways.
How many ways can a president vice president and secretary be chosen for a committee of 9 people?
There are 9*8*7 = 504 ways.
How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
There are 4 married couples in a club A 3 member committee must be formed from among them such that no married couple is part of the committee In how many ways can this committee be formed?
32
How many ways can you select 3 people out of 10?
240
How many ways can a 4 person subcommittee be selected from a committee of 8 people?
There are 8!/(4!*4!) = 70 ways.
How many ways can a president vice president and secretary be chosen for a committee of 9 people?
There are 9*8*7 = 504 ways.
A committee of 5 people must be selected from 5 accountants and 8 educators in how many ways can a selection be done if there are at least 3 educators in the committee?
560.
How many different ways can the letters of committee be arranged?
There are 45360 ways.
How many ways can a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students?
For this type of problem, order doesn't matter in which you select the number of people out of the certain group. We use combination to solve the problem.Some notes to know what is going on with this problem:• You want to form a committee of 2 teachers and 5 students to be formed from 7 teachers and 25 students • Then, you select 2 teachers out of 7 without repetition and without considering about the orders of the teachers.• Similarly, you select 5 students out out 25 without repetition and without considering about the orders of the students.Therefore, the solution is (25 choose 5)(7 choose 2) ways, which is equivalent to 1115730 ways to form such committee!
What state does congressman Mike Thompson represent?
Congressman Mike Thompson is a member of the House Committee on Ways and Means and the House Permanent Select Committee on Intelligence. Mike Thompson represents the state of California.
In how many ways can a committee of three men and four women be formed from a group of 10 men and 10 women?
I'm going with 25,200 3 men out of 10 may be chosen in 10C3 ways = 10 ! / 3! 7 ! = 120 ways. 4 women may be chosen out of 10 in 10C4 = 10 ! / 4! 6! ways = 210 ways. Therefore, a committee with 3 men and 4 women can be formed in 120 x 210 = 25,200 ways.
How many different ways are there to select a group of 4 out of 7 people for a seating arrangement in a row of length 4?
add ore people
How many subcommittees does the house ways and means committee have?
house has 106
In how many ways can a chairperson and a vice chairperson be selected from a committee of 18 senators?
18x17= 306 ways
How many different ways can 1 committee of 5 students be selected from a class of 25?
53,130 ways.
