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There are just two ways to get the value of 11 when dice are thrown. one would be a 5 and 6 and the other is a 6 and 5.

Q: How many ways can you get a sum of 11 when 2 dice are thrown?

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10 ways.

The are more ways to roll a 6 (five ways) than to roll a 4 (three ways).

Assuming you mean a sum of 4, there are three ways this can be done: (1, 3), (2, 2) and (3, 1).

5 of 36. That's about 14% if you round up.

7/12 ≈ 0.583 Probability is number_of_ways_of_success/total_number_of_ways. There are 36 possible ways 2 dice can land when thrown. To be more than 6, the sum can be 7, 8, ..., 12 There is 1 way to achieve 12 (6 & 6); 2 ways to achieve 11 (5 & 6 and 6 & 5); ... 6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1); A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6. Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.

Related questions

Two ways- one on the first die, and two on the second die, and visa versa.

10 ways.

It is 11/18.

two ways one and three and a pair of twos

count the number of times you get number 1, when you roll a pair of dice.. cheerio

The are more ways to roll a 6 (five ways) than to roll a 4 (three ways).

There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.

Assuming you mean a sum of 4, there are three ways this can be done: (1, 3), (2, 2) and (3, 1).

5 of 36. That's about 14% if you round up.

33,33333...%

3

7/12 ≈ 0.583 Probability is number_of_ways_of_success/total_number_of_ways. There are 36 possible ways 2 dice can land when thrown. To be more than 6, the sum can be 7, 8, ..., 12 There is 1 way to achieve 12 (6 & 6); 2 ways to achieve 11 (5 & 6 and 6 & 5); ... 6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1); A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6. Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.