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7/12 ≈ 0.583

Probability is number_of_ways_of_success/total_number_of_ways.

There are 36 possible ways 2 dice can land when thrown.

To be more than 6, the sum can be 7, 8, ..., 12

There is 1 way to achieve 12 (6 & 6);

2 ways to achieve 11 (5 & 6 and 6 & 5);

...

6 ways to achieve 7 (1 & 6, 2 & 5, ..., 6 & 1);

A Total of 1 + 2 + ... + 6 = 21 ways of getting a sum greater than 6.

Thus the probability of throwing a sum greater than 6 is 21/36 = 7/12.

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