60 if you allow permutations, 20 if not. 60 is found by suing the permutation function 5P3, and we get 20 simply by dividing by 3 as there will be 3 permutations from a group of 3 numbers while keeping the order the same e.g. (1,2,3) , (2,3,1) and (3,1,2).
three twenty five cents, and three one cents
There are 2300 possible combinations.
252 combinations, :)
five
There are 2^5 = 32 different combinations of the five traits possible.
There is 1 combination of all ten numbers, 10 combinations of one number and of nine numbers, 45 combinations of two or eight numbers, 120 combinations of three or seven numbers, 210 combinations of four or six numbers and 252 combinations of five numbers. That is 1023 = 210 - 1 in total.
There are 5C3 = (5*4*3)/(2*1) = 30 combinations.
one
There are several ways to express 75 cents, including using different coin combinations. For example, you can say it as three quarters, or as two quarters and five dimes, or as one quarter and five dimes plus one nickel. Additionally, you can express it in words as "seventy-five cents" or as "three-quarters of a dollar." Overall, the variations depend on the denominations and combinations of coins used.
Seven combinations that I can come up with: two dimes a nickel and three pennies all pennies two dimes and eight pennies a quarter and three pennies five nickels and three pennies three nickels one dime and three pennies two nickels one dime and eight pennies
Start with the factors. Multiply combinations of three prime factors, then combinations of five, then seven, etc. All generated numbers will be guaranteed to have an odd number of prime factors.
125