Please ! Too much information ! We don't need to know the man's weight, we don't need to know that the subject is a man, and we certainly don't need to know that you're talking about blood here. 0.5% of 6,300 mL = 0.005 x 6,300 = 31.5 mL
That all depends on what you want the final concentration of alcohol to be.
yes because, 70% alchole make easy contect with suface of the specimen
Yes, he is legally intoxicated.
This is a solution containg 60 percent isopropyl alcohol; can be used as rubbing alcohol.
The maximum alcohol percentage depends on the type of beverage. Generally, most spirits have a maximum alcohol percentage of around 40-50%, although some specialty liquors may have higher percentages. Wine typically ranges from 12-15% alcohol, while beer usually has an alcohol content ranging from 4-8%.
.08
.8 percent
6300ml x 0.5% = 6300ml x 0.005 = 31.5 ml
DWI or DUI In most states driving while intoxicated is defined as having a 0.1 percent Blood alcohol concentration(BAC), although in some states it is 0.08.
Because the concentration of alcohol is lower; you pay the alcohol not the water.
If the concentration of alcohol and water solution is 25 percent alcohol by volume, the volume of alcohol in a 200 solution is 50.
That all depends on what you want the final concentration of alcohol to be.
.08 percent
100% alcohol is more effective because of the more alcohol concentration in the drink.
I believe it's 14ml in a liter.
It is .08% it's same for Oregon
40% alcohol is 80 proof and about the average proof of many hard liquors.