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What is the weight of a box of dimes?

Updated: 8/10/2023
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11y ago

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It depends on its date.

The current U.S. dime (1965 to the present) is 0.08 avoirdupois ounce, 7/96 troy ounce (about 0.0792 troy ounce or 2.268 grams).

The U.S. dime from 1873 to 1964 was 2.500 grams (38.58 grains, 0.08038 oz troy, 0.08818 oz avoirdupois).

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13y ago
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9y ago

£1000 in 20s with a bank band weighs 55.0 g so allowing 0.5 g for the band that is 54.4g divided by fifty gives 1.09g each is worth 12.12.12.12.12.12.12.12.12.12.12.1.212.12.12.12.12.12.12.12.12.12.12.12.12..222.222.2 u.s. dollars

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14y ago
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The standard weight of a US dime dated 1965 or later is 2.268 grams.

Older silver dimes weigh 2.5 grams.

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11y ago

About 12.lbs. One roll is apparently 113.4 grams and there are 50 rolls in a box.

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12y ago

20 dollars in nickels weighs 2 kilogram, since each 5 cent coin weighs 5 grams and 400 of them equal 20 dollars.

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13y ago

400 nickels weighs 4.41 pounds.

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15y ago

It weighs one pound.

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13y ago

2 grams

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Q: What is the weight of a box of dimes?
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How much do 50 dimes weigh?

The weight of 50 dimes would depend upon when the dimes were minted. For dimes minted from 1873 to 1964 the weight of 50 of them would be 125 grams or 4.02 troy ounces. If the 50 dimes were minted from 1965 to 2009 then the weight of them would be 113.5 grams or 3.65 troy ounces.


What does a 10 cent coin weigh?

2.268 grams. All US Dimes have the same weight.


Henrietta has a box of fruit with a mass of 88 dekagrams. What is the weight of the box of fruit in kilograms?

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Is pushing a box but it doesn't move unbalanced or balanced force?

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Average weight of 100 screws in box 'A' is 10.4gms it is mixed withed with150 screws of box 'B' average weight of mixed screws is 10.9 gms find the average weight of screws of box 'B'?

Let 'x' be the total weight of 100 screws in box 'A' therefore, average weight of 100 screws in box 'A' = (x / 100) = 10.4 => x = 100*10.4 = 1040 gms ............ (1) Let 'y' be the total weight of 150 screws in box 'B', therefore, average weight of 150 screws in box 'B' = (y / 150) .......... (2) After mixing 100 screws of 'A' and 150 screws of 'B', average weight of 250 screws = (x+y)/250 = 10.9 => x+y = 250*10.9 = 2725 => 1040+y = 2725 => y = 2725 - 1040 = 1685 => total weight of 150 screws of box 'B', y = 1685 gms Substitute y = 1685 in eqn (2), => average weight of screws of box 'B' = 1685/150 = 11.23 gms (approx) Hence, average weight of screws of box 'B' = 11.23 gms SHORT ANSWER """"""""""""""""" Given data: No. of screws in box 'A', NA = 100 No. of screws in box 'B', NB = 150 Average weight of 100 screws in box 'A', XA = 10.4 gms Average weight of mixed screws, XAB = 10.9 gms Average weight of 150 screws in box 'B', XB = ? Therefore, XAB = (NA XA + NB XB) / (NA + NB) 10.9 = (100*10.4 + 150XB) / (100+150) 10.9 = (1040 + 150XB) / 250 10.9*250 = 1040 + 150XB 2725 = 1040 + 150XB 2725 - 1040 = 150XB 1685 = 150XB XB = 1685/150 = 11.23 gms XB = 11.23 gms - Ratnakar Sharma