Assuming the pool is the shape of a perfect circle, the shape of the pool would be a cylindrical solid. The volume of a cylindrical solid is determined by multiplying the area of the circle at one end by the length of the cyllinder. In this case: (pi x r x r) x h 3.14 x 5 x 5 x 3 = 235.61944875 cubic feet The weight of water is 62.42796 pounds per cubic foot. Therefore, not including the weight of the actual pool, the weight of the filled pool would be 14706 pounds, 3.8 ounces, or 7 tons, 706 pounds, 3.8 ounces.
Here's a formula for round pools:
distance across*distance across*depth*5.9
for rectangles:
length*width*depth*7.5
or for a deep end:
length*width*((shallow end depth + deep end depth)/2)*7.5
so in your case, 10*10*2.5*5.9=1500 gallons
The area is pi times diameter squared over 4 or
3.14x10*10/4 = 78.5 sq ft
the volume is height times area or
3 x 78.5 = 235.5 cu ft
there are 7.48 gallons in a cu ft so there are
7.48 x 235.5 = 1761 gallons of water
The pool has a volume of 196.35 cu ft and a maximum capacity of 1,468.9 gallons.
To fill it the pool to a depth of three feet would require about 1,770 gallons of water.
7.48 gallons per cubic foot * 20 feet * 10 feet * 3.5 feet = 5236 gallons
25 pounds
Filled to the top, this well would hold about 956 gallons of water.
it depends how big the foot is.
40
Assuming that the pool diamater diminishes 1 foot for each foot of height, and the pool is filled to the top, the total capacity would be about 6439 gallons.
The weight of 1 foot of steel rod would depend on the diameter of the rod.
A round pool with a 10-foot diameter and a 3-foot depth can hold up to 1,762 gallons of water.
The Answers community requested more information for this question. Please edit your question to include more context. You need to specify the units for the inside diameter.
this question has no meaning
They would be way too heavy if you fill them with water.
The volume of water in a 4-inch diameter, 1-foot section of pipe is 0.6528 gallons of water.
31.987 gallons per foot.