Heat of vaporization of water is 2.26 x 106 joules per kg.
Therefore 1 gram of water will need 2.26 x 103 joules.
It is not zero so the question is based on a false assumption.
No. Those are units of temperature. Heat is measured in units of energy, such as the joule.
That depends on the amount of water, on how cold it was initially, and on how fast heat energy is supplied.
Three temperature scales are in common use in science and industry. Two of those scales are SI metric: The degree Celsius (°C) scale was devised by dividing the range of temperature between the freezing and boiling temperatures of pure water at standard atmospheric conditions (sea level pressure) into 100 equal parts. Temperatures on this scale were at one time known as degrees centigrade, however it is no longer correct to use that terminology. [The official name was changed from "centigrade degree" to "Celsius degree" by the 9th General Conference on Weights and Measures (CGPM) in 1948.] The kelvin (K)temperature scale is an extension of the degree Celsius scale down to absolute zero, a hypothetical temperature characterized by a complete absence of heat energy. Temperatures on this scale are called kelvins, NOT degrees kelvin, kelvin is not capitalized, and the symbol (capital K) stands alone with no degree symbol. [The official name was changed to "kelvin" and symbol "K" by the 13th General Conference on Weights and Measures (CGPM) in 1967.] The degree Fahrenheit (°F)non-metric temperature scale was devised and evolved over time so that the freezing and boiling temperatures of water are whole numbers, but not round numbers as in the Celsius temperature scale.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
You can't convert units of temperature to units of energy.
Steam has enough kinetic energy to leave the liquid water that is boiling, so it's greater amount of energy results in more severe burns than boiling water, which has a lower amount of energy.
It is not zero so the question is based on a false assumption.
No. Those are units of temperature. Heat is measured in units of energy, such as the joule.
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
300 calories, which is equal to about 1255.2 joules
A calorie is the amount of heat required to warm 1 gram of water one degree Centigrade. A Calorie spelt with a big "C" is a kilocalorie and is used in evaluating food energy. It is the heat required to raise 1 kilogram of water one Centigrade degree. On an energy basis a calorie is 41 840 000 ergs.
Yes, your body uses a thermal energy known as caloric energy called "calories." A calorie is the amount of thermal energy required to heat one gram of water by one degree centigrade.
You cannot. Absolute zero (the temperature at which there is no thermal energy in an atomic lattice) is −273.15 degrees centigrade, or 0K (K = Kelvin). To reach this exact temperature is impossible, but by use of a "cryocooler" temperatures very near it can be reached.
4186 Joules per liter per deg C. Not clear if we are raising the temperature BY 135 deg or TO 135 deg. So the answer is 4186 x 100 x rise in temperature. (Joules).
Twenty percent of the worlds energy is supplied by natural gas.
More specific heat means you need more heat energy to, for example, raise one kilogram of a substance by one degree centigrade.