100-81=19
.100
To determine if 0.805 is greater than 81%, we need to convert 81% to a decimal. To do this, we divide 81 by 100, which equals 0.81. Comparing 0.805 to 0.81, we see that 0.805 is indeed greater than 81%.
64, 81, 100
7^2=49 < 50 < 8^2=64 < 9^2=81 < 10^2=100 < 110 < 11^2=121 so there are 3 perfect squares greater than 50 and less than 100 viz. 64, 81 and 100.
-28
0.9 is greater
anything from .81 and greater... ha.
It is 81
Yes.
To find the last two digits of 81 mod 100, we calculate ( 81 \mod 100 ). Since 81 is less than 100, the result is simply 81. Therefore, the last two digits of 81 mod 100 are 81.
There are several, but here are four: 108, 117, 189, 198.
No.