If we assume that the mass of paper is the same in a bill of each denomination, and
the mass of ink in each is also the same, then the value of any mass of $10-bills is
10 times the value of the same mass of $1-bills.
So the difference in their value is nine times the number of bills in either pile.
There were no 1901 dollar bills
10
10
Reading the question very carefully, I'd have to say "none". If the stack consists of "900 dollar bills",then there are no "50 dollar bills" in it.But the questioner is probably referring to equivalent values.900 dollar bills have a face value of $900.00 . In order to match that same face value with $50.00 bills,you need 18 of them.
10 ten dollar bills
If there are d $1 bills their value is $1 × d, or d dollars.Each $5 bills is worth 5 times as much so if there are f bills their value is $5 × f, or 5f dollars.Thus the expression for the total would be d + 5f dollars.
$4
There weren't dollar bills in 1775 and the first dollar bills didn't happen until 1862.
Let's denote the number of five dollar bills as x and the number of ten dollar bills as y. We can set up a system of equations based on the given information: 5x + 10y = 175 (total value of the bills) x + y = 25 (total number of bills) Solving this system of equations, we find that there are 15 ten dollar bills in Perry's pocket.
$245
$245
There are no U.S. ten dollar bills with that date. In any case bills dated 1963 and later are mostly only worth face value.