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Q = m*c*delta T

c for coal = 0.24 (depending on its origin)

Q = 5*0.24*(220-20) = 240 Joules

c for anthracite coal is also given as 0.201 which will give an answer of 201 Joules

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Q: How much heat energy is required to raise the temperature of 5 kilograms of coal from 20degree C to 220 degree C?
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