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How much heat is released as 5 grams of water vapor cools from 150 degrees celsius to 105 degrees celsius?
Wiki User
∙ 14y ago
Q = mc(dT) where dT = the change in temperature of the substance.
Knowing that the specific heat of water (c) is 4.186 J/g C and that m = 5g we can find the solution.
Q = (5g)(4.186 J/g C)(150-105)C
Q = 941.85 J
Wiki User
∙ 14y ago
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